12+3k=5(k+2)+2

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Solution for 12+3k=5(k+2)+2 equation: 



12+3k=5(k+2)+2

We move all terms to the left:

12+3k-(5(k+2)+2)=0



We calculate terms in parentheses: -(5(k+2)+2), so:

5(k+2)+2

We multiply parentheses

5k+10+2

We add all the numbers together, and all the variables

5k+12

Back to the equation:

-(5k+12)



We get rid of parentheses

3k-5k-12+12=0

We add all the numbers together, and all the variables

-2k=0

k=0/-2

k=0

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