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3(x-5)=6(x+8)+6x
We move all terms to the left:
3(x-5)-(6(x+8)+6x)=0
We multiply parentheses
3x-(6(x+8)+6x)-15=0
We calculate terms in parentheses: -(6(x+8)+6x), so:We get rid of parentheses
6(x+8)+6x
We add all the numbers together, and all the variables
6x+6(x+8)
We multiply parentheses
6x+6x+48
We add all the numbers together, and all the variables
12x+48
Back to the equation:
-(12x+48)
3x-12x-48-15=0
We add all the numbers together, and all the variables
-9x-63=0
We move all terms containing x to the left, all other terms to the right
-9x=63
x=63/-9
x=-7
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