1-(2-(3+x))=4x-(6+x)

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Solution for 1-(2-(3+x))=4x-(6+x) equation: 



1-(2-(3+x))=4x-(6+x)

We move all terms to the left:

1-(2-(3+x))-(4x-(6+x))=0

We add all the numbers together, and all the variables

-(2-(x+3))-(4x-(x+6))+1=0



We calculate terms in parentheses: -(2-(x+3)), so:

2-(x+3)

determiningTheFunctionDomain
-(x+3)+2

We get rid of parentheses

-x-3+2

We add all the numbers together, and all the variables

-1x-1

Back to the equation:

-(-1x-1)





We calculate terms in parentheses: -(4x-(x+6)), so:

4x-(x+6)

We get rid of parentheses

4x-x-6

We add all the numbers together, and all the variables

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

1x-3x+1+6+1=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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