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6x(x+4)=72
We move all terms to the left:
6x(x+4)-(72)=0
We multiply parentheses
6x^2+24x-72=0
a = 6; b = 24; c = -72;
Δ = b2-4ac
Δ = 242-4·6·(-72)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-48}{2*6}=\frac{-72}{12} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+48}{2*6}=\frac{24}{12} =2 $
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