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3(x-5)=4(2x+1)+1
We move all terms to the left:
3(x-5)-(4(2x+1)+1)=0
We multiply parentheses
3x-(4(2x+1)+1)-15=0
We calculate terms in parentheses: -(4(2x+1)+1), so:We get rid of parentheses
4(2x+1)+1
We multiply parentheses
8x+4+1
We add all the numbers together, and all the variables
8x+5
Back to the equation:
-(8x+5)
3x-8x-5-15=0
We add all the numbers together, and all the variables
-5x-20=0
We move all terms containing x to the left, all other terms to the right
-5x=20
x=20/-5
x=-4
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