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3(x-5)=2(x+)
We move all terms to the left:
3(x-5)-(2(x+))=0
We add all the numbers together, and all the variables
3(x-5)-(2(+x))=0
We multiply parentheses
3x-(2(+x))-15=0
We calculate terms in parentheses: -(2(+x)), so:We add all the numbers together, and all the variables
2(+x)
We multiply parentheses
2x
Back to the equation:
-(2x)
x-15=0
We move all terms containing x to the left, all other terms to the right
x=15
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