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3(x-5)=2(5-4x)
We move all terms to the left:
3(x-5)-(2(5-4x))=0
We add all the numbers together, and all the variables
3(x-5)-(2(-4x+5))=0
We multiply parentheses
3x-(2(-4x+5))-15=0
We calculate terms in parentheses: -(2(-4x+5)), so:We get rid of parentheses
2(-4x+5)
We multiply parentheses
-8x+10
Back to the equation:
-(-8x+10)
3x+8x-10-15=0
We add all the numbers together, and all the variables
11x-25=0
We move all terms containing x to the left, all other terms to the right
11x=25
x=25/11
x=2+3/11
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