8(11-2b)=4(4b+22)

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Solution for 8(11-2b)=4(4b+22) equation: 



8(11-2b)=4(4b+22)

We move all terms to the left:

8(11-2b)-(4(4b+22))=0

We add all the numbers together, and all the variables

8(-2b+11)-(4(4b+22))=0

We multiply parentheses

-16b-(4(4b+22))+88=0



We calculate terms in parentheses: -(4(4b+22)), so:

4(4b+22)

We multiply parentheses

16b+88

Back to the equation:

-(16b+88)



We get rid of parentheses

-16b-16b-88+88=0

We add all the numbers together, and all the variables

-32b=0

b=0/-32

b=0

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