3(x-5)-4(2x-4)=-2(x-8)*

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Solution for 3(x-5)-4(2x-4)=-2(x-8)* equation: 



3(x-5)-4(2x-4)=-2(x-8)*

We move all terms to the left:

3(x-5)-4(2x-4)-(-2(x-8)*)=0

We multiply parentheses

3x-8x-(-2(x-8)*)-15+16=0



We calculate terms in parentheses: -(-2(x-8)*), so:

-2(x-8)*

We multiply parentheses

-2x+16

Back to the equation:

-(-2x+16)



We add all the numbers together, and all the variables

-5x-(-2x+16)+1=0

We get rid of parentheses

-5x+2x-16+1=0

We add all the numbers together, and all the variables

-3x-15=0

We move all terms containing x to the left, all other terms to the right

-3x=15

x=15/-3

x=-5

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