25(x-1)=5(5-x)+20x

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Solution for 25(x-1)=5(5-x)+20x equation: 



25(x-1)=5(5-x)+20x

We move all terms to the left:

25(x-1)-(5(5-x)+20x)=0

We add all the numbers together, and all the variables

25(x-1)-(5(-1x+5)+20x)=0

We multiply parentheses

25x-(5(-1x+5)+20x)-25=0



We calculate terms in parentheses: -(5(-1x+5)+20x), so:

5(-1x+5)+20x

We add all the numbers together, and all the variables

20x+5(-1x+5)

We multiply parentheses

20x-5x+25

We add all the numbers together, and all the variables

15x+25

Back to the equation:

-(15x+25)



We get rid of parentheses

25x-15x-25-25=0

We add all the numbers together, and all the variables

10x-50=0

We move all terms containing x to the left, all other terms to the right

10x=50

x=50/10

x=5

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