3(x-5)-2(1-x)=-3(4-x)+3

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Solution for 3(x-5)-2(1-x)=-3(4-x)+3 equation:



3(x-5)-2(1-x)=-3(4-x)+3
We move all terms to the left:
3(x-5)-2(1-x)-(-3(4-x)+3)=0
We add all the numbers together, and all the variables
3(x-5)-2(-1x+1)-(-3(-1x+4)+3)=0
We multiply parentheses
3x+2x-(-3(-1x+4)+3)-15-2=0
We calculate terms in parentheses: -(-3(-1x+4)+3), so:
-3(-1x+4)+3
We multiply parentheses
3x-12+3
We add all the numbers together, and all the variables
3x-9
Back to the equation:
-(3x-9)
We add all the numbers together, and all the variables
5x-(3x-9)-17=0
We get rid of parentheses
5x-3x+9-17=0
We add all the numbers together, and all the variables
2x-8=0
We move all terms containing x to the left, all other terms to the right
2x=8
x=8/2
x=4

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