6(y-4)-8y=-30

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Solution for 6(y-4)-8y=-30 equation: 



6(y-4)-8y=-30

We move all terms to the left:

6(y-4)-8y-(-30)=0

We add all the numbers together, and all the variables

-8y+6(y-4)+30=0

We multiply parentheses

-8y+6y-24+30=0

We add all the numbers together, and all the variables

-2y+6=0

We move all terms containing y to the left, all other terms to the right

-2y=-6

y=-6/-2

y=+3

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