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3(x-5)+x=4(x-6)+9
We move all terms to the left:
3(x-5)+x-(4(x-6)+9)=0
We add all the numbers together, and all the variables
x+3(x-5)-(4(x-6)+9)=0
We multiply parentheses
x+3x-(4(x-6)+9)-15=0
We calculate terms in parentheses: -(4(x-6)+9), so:We add all the numbers together, and all the variables
4(x-6)+9
We multiply parentheses
4x-24+9
We add all the numbers together, and all the variables
4x-15
Back to the equation:
-(4x-15)
4x-(4x-15)-15=0
We get rid of parentheses
4x-4x+15-15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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