(x+1)/2=1-(x+6)/5

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Solution for (x+1)/2=1-(x+6)/5 equation: 



(x+1)/2=1-(x+6)/5

We move all terms to the left:

(x+1)/2-(1-(x+6)/5)=0

We calculate fractions


x/()+(-(1-(x+6)*2)/()=0



We calculate terms in parentheses: +(-(1-(x+6)*2)/(), so:

-(1-(x+6)*2)/(

We multiply all the terms by the denominator


-(1-(x+6)*2)



We calculate terms in parentheses: -(1-(x+6)*2), so:

1-(x+6)*2

determiningTheFunctionDomain
-(x+6)*2+1

We multiply parentheses

-2x-12+1

We add all the numbers together, and all the variables

-2x-11

Back to the equation:

-(-2x-11)



We get rid of parentheses

2x+11

Back to the equation:

+(2x+11)



We get rid of parentheses

x/()+2x+11=0

We multiply all the terms by the denominator


x+2x*()+11*()=0

We add all the numbers together, and all the variables

x+2x*()=0

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