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3(x-5)+2x=4(x-4)=x=1
We move all terms to the left:
3(x-5)+2x-(4(x-4))=0
We add all the numbers together, and all the variables
2x+3(x-5)-(4(x-4))=0
We multiply parentheses
2x+3x-(4(x-4))-15=0
We calculate terms in parentheses: -(4(x-4)), so:We add all the numbers together, and all the variables
4(x-4)
We multiply parentheses
4x-16
Back to the equation:
-(4x-16)
5x-(4x-16)-15=0
We get rid of parentheses
5x-4x+16-15=0
We add all the numbers together, and all the variables
x+1=0
We move all terms containing x to the left, all other terms to the right
x=-1
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