1/3(3x+6x-6)+(4x+1)=90

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Solution for 1/3(3x+6x-6)+(4x+1)=90 equation: 



1/3(3x+6x-6)+(4x+1)=90

We move all terms to the left:

1/3(3x+6x-6)+(4x+1)-(90)=0



Domain of the equation: 3(3x+6x-6)!=0

x∈R



We add all the numbers together, and all the variables

1/3(9x-6)+(4x+1)-90=0

We get rid of parentheses

1/3(9x-6)+4x+1-90=0

We multiply all the terms by the denominator


4x*3(9x-6)+1*3(9x-6)-90*3(9x-6)+1=0

Wy multiply elements

12x^2(9+3x(9-270x(9+1=0

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