7-3x=3x-4(2+x)

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Solution for 7-3x=3x-4(2+x) equation: 



7-3x=3x-4(2+x)

We move all terms to the left:

7-3x-(3x-4(2+x))=0

We add all the numbers together, and all the variables

-3x-(3x-4(x+2))+7=0



We calculate terms in parentheses: -(3x-4(x+2)), so:

3x-4(x+2)

We multiply parentheses

3x-4x-8

We add all the numbers together, and all the variables

-1x-8

Back to the equation:

-(-1x-8)



We get rid of parentheses

-3x+1x+8+7=0

We add all the numbers together, and all the variables

-2x+15=0

We move all terms containing x to the left, all other terms to the right

-2x=-15

x=-15/-2

x=7+1/2

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