3(x-5)+12x+10=7(2x-3)+10

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Solution for 3(x-5)+12x+10=7(2x-3)+10 equation: 



3(x-5)+12x+10=7(2x-3)+10

We move all terms to the left:

3(x-5)+12x+10-(7(2x-3)+10)=0

We add all the numbers together, and all the variables

12x+3(x-5)-(7(2x-3)+10)+10=0

We multiply parentheses

12x+3x-(7(2x-3)+10)-15+10=0



We calculate terms in parentheses: -(7(2x-3)+10), so:

7(2x-3)+10

We multiply parentheses

14x-21+10

We add all the numbers together, and all the variables

14x-11

Back to the equation:

-(14x-11)



We add all the numbers together, and all the variables

15x-(14x-11)-5=0

We get rid of parentheses

15x-14x+11-5=0

We add all the numbers together, and all the variables

x+6=0

We move all terms containing x to the left, all other terms to the right

x=-6

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