3(x-4)=7(x+8)

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Solution for 3(x-4)=7(x+8) equation: 



3(x-4)=7(x+8)

We move all terms to the left:

3(x-4)-(7(x+8))=0

We multiply parentheses

3x-(7(x+8))-12=0



We calculate terms in parentheses: -(7(x+8)), so:

7(x+8)

We multiply parentheses

7x+56

Back to the equation:

-(7x+56)



We get rid of parentheses

3x-7x-56-12=0

We add all the numbers together, and all the variables

-4x-68=0

We move all terms containing x to the left, all other terms to the right

-4x=68

x=68/-4

x=-17

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