-2(u+5)=2u-2+2(7u+4)

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Solution for -2(u+5)=2u-2+2(7u+4) equation: 



-2(u+5)=2u-2+2(7u+4)

We move all terms to the left:

-2(u+5)-(2u-2+2(7u+4))=0

We multiply parentheses

-2u-(2u-2+2(7u+4))-10=0



We calculate terms in parentheses: -(2u-2+2(7u+4)), so:

2u-2+2(7u+4)

determiningTheFunctionDomain
2u+2(7u+4)-2

We multiply parentheses

2u+14u+8-2

We add all the numbers together, and all the variables

16u+6

Back to the equation:

-(16u+6)



We get rid of parentheses

-2u-16u-6-10=0

We add all the numbers together, and all the variables

-18u-16=0

We move all terms containing u to the left, all other terms to the right

-18u=16

u=16/-18

u=-8/9

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