3(x-4)=6x-(3x+12)

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Solution for 3(x-4)=6x-(3x+12) equation: 



3(x-4)=6x-(3x+12)

We move all terms to the left:

3(x-4)-(6x-(3x+12))=0

We multiply parentheses

3x-(6x-(3x+12))-12=0



We calculate terms in parentheses: -(6x-(3x+12)), so:

6x-(3x+12)

We get rid of parentheses

6x-3x-12

We add all the numbers together, and all the variables

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

3x-3x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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