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(x+3)/(2x-1)=-3
We move all terms to the left:
(x+3)/(2x-1)-(-3)=0
Domain of the equation: (2x-1)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x!=1
x!=1/2
x!=1/2
x∈R
(x+3)/(2x-1)+3=0
We multiply all the terms by the denominator
(x+3)+3*(2x-1)=0
We multiply parentheses
(x+3)+6x-3=0
We get rid of parentheses
x+6x+3-3=0
We add all the numbers together, and all the variables
7x=0
x=0/7
x=0
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