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10(x+4)-4(x+8)=2(x+4)+4x
We move all terms to the left:
10(x+4)-4(x+8)-(2(x+4)+4x)=0
We multiply parentheses
10x-4x-(2(x+4)+4x)+40-32=0
We calculate terms in parentheses: -(2(x+4)+4x), so:We add all the numbers together, and all the variables
2(x+4)+4x
We add all the numbers together, and all the variables
4x+2(x+4)
We multiply parentheses
4x+2x+8
We add all the numbers together, and all the variables
6x+8
Back to the equation:
-(6x+8)
6x-(6x+8)+8=0
We get rid of parentheses
6x-6x-8+8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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