5p(2)+9p-4=0

Solution for 5p(2)+9p-4=0 equation:

5p(2)+9p-4=0

We add all the numbers together, and all the variables

5p^2+9p-4=0

a = 5; b = 9; c = -4;
Δ = b2-4ac
Δ = 92-4·5·(-4)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{161}}{2*5}=\frac{-9-\sqrt{161}}{10}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{161}}{2*5}=\frac{-9+\sqrt{161}}{10}
$