3(x-4)=4+7x

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Solution for 3(x-4)=4+7x equation: 



3(x-4)=4+7x

We move all terms to the left:

3(x-4)-(4+7x)=0

We add all the numbers together, and all the variables

3(x-4)-(7x+4)=0

We multiply parentheses

3x-(7x+4)-12=0

We get rid of parentheses

3x-7x-4-12=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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