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(y+1)/2y+3=3/8
We move all terms to the left:
(y+1)/2y+3-(3/8)=0
Domain of the equation: 2y!=0We add all the numbers together, and all the variables
y!=0/2
y!=0
y∈R
(y+1)/2y+3-(+3/8)=0
We get rid of parentheses
(y+1)/2y+3-3/8=0
We calculate fractions
(8y+8)/16y+(-6y)/16y+3=0
We multiply all the terms by the denominator
(8y+8)+(-6y)+3*16y=0
Wy multiply elements
(8y+8)+(-6y)+48y=0
We get rid of parentheses
8y-6y+48y+8=0
We add all the numbers together, and all the variables
50y+8=0
We move all terms containing y to the left, all other terms to the right
50y=-8
y=-8/50
y=-4/25
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