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4(x-3)=5(6-x)+3
We move all terms to the left:
4(x-3)-(5(6-x)+3)=0
We add all the numbers together, and all the variables
4(x-3)-(5(-1x+6)+3)=0
We multiply parentheses
4x-(5(-1x+6)+3)-12=0
We calculate terms in parentheses: -(5(-1x+6)+3), so:We get rid of parentheses
5(-1x+6)+3
We multiply parentheses
-5x+30+3
We add all the numbers together, and all the variables
-5x+33
Back to the equation:
-(-5x+33)
4x+5x-33-12=0
We add all the numbers together, and all the variables
9x-45=0
We move all terms containing x to the left, all other terms to the right
9x=45
x=45/9
x=5
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