3(x-4)=2x+2(3x-2)

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Solution for 3(x-4)=2x+2(3x-2) equation: 



3(x-4)=2x+2(3x-2)

We move all terms to the left:

3(x-4)-(2x+2(3x-2))=0

We multiply parentheses

3x-(2x+2(3x-2))-12=0



We calculate terms in parentheses: -(2x+2(3x-2)), so:

2x+2(3x-2)

We multiply parentheses

2x+6x-4

We add all the numbers together, and all the variables

8x-4

Back to the equation:

-(8x-4)



We get rid of parentheses

3x-8x+4-12=0

We add all the numbers together, and all the variables

-5x-8=0

We move all terms containing x to the left, all other terms to the right

-5x=8

x=8/-5

x=-1+3/5

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