9f=1/2)12f-2)

Solution for 9f=1/2)12f-2) equation:

9f=1/2)12f-2)

We move all terms to the left:

9f-(1/2)12f-2))=0


Domain of the equation: 2)12f!=0

f!=0/1

f!=0

f∈R


We add all the numbers together, and all the variables

9f-(+1/2)12f-2))=0

We add all the numbers together, and all the variables

9f-(+1/2)12f=0

We multiply parentheses

-12f^2+9f=0

a = -12; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-12)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-12}=\frac{-18}{-24}
=3/4
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-12}=\frac{0}{-24}
=0
$