3(x-4)=2(-2x-+1)

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Solution for 3(x-4)=2(-2x-+1) equation: 



3(x-4)=2(-2x-+1)

We move all terms to the left:

3(x-4)-(2(-2x-+1))=0

We add all the numbers together, and all the variables

3(x-4)-(2(-2x))=0

We multiply parentheses

3x-(2(-2x))-12=0



We calculate terms in parentheses: -(2(-2x)), so:

2(-2x)

We multiply parentheses

-4x

Back to the equation:

-(-4x)



We get rid of parentheses

3x+4x-12=0

We add all the numbers together, and all the variables

7x-12=0

We move all terms containing x to the left, all other terms to the right

7x=12

x=12/7

x=1+5/7

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