-4(2-b)=10(b-3)

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Solution for -4(2-b)=10(b-3) equation: 



-4(2-b)=10(b-3)

We move all terms to the left:

-4(2-b)-(10(b-3))=0

We add all the numbers together, and all the variables

-4(-1b+2)-(10(b-3))=0

We multiply parentheses

4b-(10(b-3))-8=0



We calculate terms in parentheses: -(10(b-3)), so:

10(b-3)

We multiply parentheses

10b-30

Back to the equation:

-(10b-30)



We get rid of parentheses

4b-10b+30-8=0

We add all the numbers together, and all the variables

-6b+22=0

We move all terms containing b to the left, all other terms to the right

-6b=-22

b=-22/-6

b=3+2/3

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