8(z+2)-(9z-4)=-2z

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Solution for 8(z+2)-(9z-4)=-2z equation: 



8(z+2)-(9z-4)=-2z

We move all terms to the left:

8(z+2)-(9z-4)-(-2z)=0

We multiply parentheses

8z-(9z-4)-(-2z)+16=0

We get rid of parentheses

8z-9z+2z+4+16=0

We add all the numbers together, and all the variables

z+20=0

We move all terms containing z to the left, all other terms to the right

z=-20

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