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3(x-4)5x+2=1
We move all terms to the left:
3(x-4)5x+2-(1)=0
We add all the numbers together, and all the variables
3(x-4)5x+1=0
We multiply parentheses
15x^2-60x+1=0
a = 15; b = -60; c = +1;
Δ = b2-4ac
Δ = -602-4·15·1
Δ = 3540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3540}=\sqrt{4*885}=\sqrt{4}*\sqrt{885}=2\sqrt{885}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-2\sqrt{885}}{2*15}=\frac{60-2\sqrt{885}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+2\sqrt{885}}{2*15}=\frac{60+2\sqrt{885}}{30} $
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