42=2/3(18x+12)-2

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Solution for 42=2/3(18x+12)-2 equation: 



42=2/3(18x+12)-2

We move all terms to the left:

42-(2/3(18x+12)-2)=0



Domain of the equation: 3(18x+12)-2)!=0

x∈R



We multiply all the terms by the denominator


-(2+42*3(18x+12)-2)=0



We calculate terms in parentheses: -(2+42*3(18x+12)-2), so:

2+42*3(18x+12)-2

determiningTheFunctionDomain
42*3(18x+12)+2-2

We add all the numbers together, and all the variables

42*3(18x+12)

Wy multiply elements

126x(1

Back to the equation:

-(126x(1)

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