3(x-4)-2x-8=9(x+2)+1

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Solution for 3(x-4)-2x-8=9(x+2)+1 equation: 



3(x-4)-2x-8=9(x+2)+1

We move all terms to the left:

3(x-4)-2x-8-(9(x+2)+1)=0

We add all the numbers together, and all the variables

-2x+3(x-4)-(9(x+2)+1)-8=0

We multiply parentheses

-2x+3x-(9(x+2)+1)-12-8=0



We calculate terms in parentheses: -(9(x+2)+1), so:

9(x+2)+1

We multiply parentheses

9x+18+1

We add all the numbers together, and all the variables

9x+19

Back to the equation:

-(9x+19)



We add all the numbers together, and all the variables

x-(9x+19)-20=0

We get rid of parentheses

x-9x-19-20=0

We add all the numbers together, and all the variables

-8x-39=0

We move all terms containing x to the left, all other terms to the right

-8x=39

x=39/-8

x=-4+7/8

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