8a-(-3-5a)2a=

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Solution for 8a-(-3-5a)2a= equation:



8a-(-3-5a)2a=
We move all terms to the left:
8a-(-3-5a)2a-()=0
We add all the numbers together, and all the variables
8a-(-5a-3)2a-()=0
We add all the numbers together, and all the variables
8a-(-5a-3)2a=0
We multiply parentheses
10a^2+8a+6a=0
We add all the numbers together, and all the variables
10a^2+14a=0
a = 10; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·10·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*10}=\frac{-28}{20} =-1+2/5 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*10}=\frac{0}{20} =0 $

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