3(x-4)-2(3x+5)=4(3-x)+5x+4

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Solution for 3(x-4)-2(3x+5)=4(3-x)+5x+4 equation: 



3(x-4)-2(3x+5)=4(3-x)+5x+4

We move all terms to the left:

3(x-4)-2(3x+5)-(4(3-x)+5x+4)=0

We add all the numbers together, and all the variables

3(x-4)-2(3x+5)-(4(-1x+3)+5x+4)=0

We multiply parentheses

3x-6x-(4(-1x+3)+5x+4)-12-10=0



We calculate terms in parentheses: -(4(-1x+3)+5x+4), so:

4(-1x+3)+5x+4

We add all the numbers together, and all the variables

5x+4(-1x+3)+4

We multiply parentheses

5x-4x+12+4

We add all the numbers together, and all the variables

x+16

Back to the equation:

-(x+16)



We add all the numbers together, and all the variables

-3x-(x+16)-22=0

We get rid of parentheses

-3x-x-16-22=0

We add all the numbers together, and all the variables

-4x-38=0

We move all terms containing x to the left, all other terms to the right

-4x=38

x=38/-4

x=-9+1/2

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