3(x-4)+x=4(x-2)+1

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Solution for 3(x-4)+x=4(x-2)+1 equation: 



3(x-4)+x=4(x-2)+1

We move all terms to the left:

3(x-4)+x-(4(x-2)+1)=0

We add all the numbers together, and all the variables

x+3(x-4)-(4(x-2)+1)=0

We multiply parentheses

x+3x-(4(x-2)+1)-12=0



We calculate terms in parentheses: -(4(x-2)+1), so:

4(x-2)+1

We multiply parentheses

4x-8+1

We add all the numbers together, and all the variables

4x-7

Back to the equation:

-(4x-7)



We add all the numbers together, and all the variables

4x-(4x-7)-12=0

We get rid of parentheses

4x-4x+7-12=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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