5/6x-1/3x-7=3

Solution for 5/6x-1/3x-7=3 equation:

5/6x-1/3x-7=3

We move all terms to the left:

5/6x-1/3x-7-(3)=0


Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

5/6x-1/3x-10=0

We calculate fractions


15x/18x^2+(-6x)/18x^2-10=0

We multiply all the terms by the denominator


15x+(-6x)-10*18x^2=0

Wy multiply elements

-180x^2+15x+(-6x)=0

We get rid of parentheses

-180x^2+15x-6x=0

We add all the numbers together, and all the variables

-180x^2+9x=0

a = -180; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-180)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-180}=\frac{-18}{-360}
=1/20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-180}=\frac{0}{-360}
=0
$