3(x-4)+x=4(3-x)

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Solution for 3(x-4)+x=4(3-x) equation: 



3(x-4)+x=4(3-x)

We move all terms to the left:

3(x-4)+x-(4(3-x))=0

We add all the numbers together, and all the variables

3(x-4)+x-(4(-1x+3))=0

We add all the numbers together, and all the variables

x+3(x-4)-(4(-1x+3))=0

We multiply parentheses

x+3x-(4(-1x+3))-12=0



We calculate terms in parentheses: -(4(-1x+3)), so:

4(-1x+3)

We multiply parentheses

-4x+12

Back to the equation:

-(-4x+12)



We add all the numbers together, and all the variables

4x-(-4x+12)-12=0

We get rid of parentheses

4x+4x-12-12=0

We add all the numbers together, and all the variables

8x-24=0

We move all terms containing x to the left, all other terms to the right

8x=24

x=24/8

x=3

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