3(x-4)+6=2(x-2)+5

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Solution for 3(x-4)+6=2(x-2)+5 equation: 



3(x-4)+6=2(x-2)+5

We move all terms to the left:

3(x-4)+6-(2(x-2)+5)=0

We multiply parentheses

3x-(2(x-2)+5)-12+6=0



We calculate terms in parentheses: -(2(x-2)+5), so:

2(x-2)+5

We multiply parentheses

2x-4+5

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We add all the numbers together, and all the variables

3x-(2x+1)-6=0

We get rid of parentheses

3x-2x-1-6=0

We add all the numbers together, and all the variables

x-7=0

We move all terms containing x to the left, all other terms to the right

x=7

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