3(x-4)+5x=4x+4(x-3)

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Solution for 3(x-4)+5x=4x+4(x-3) equation: 



3(x-4)+5x=4x+4(x-3)

We move all terms to the left:

3(x-4)+5x-(4x+4(x-3))=0

We add all the numbers together, and all the variables

5x+3(x-4)-(4x+4(x-3))=0

We multiply parentheses

5x+3x-(4x+4(x-3))-12=0



We calculate terms in parentheses: -(4x+4(x-3)), so:

4x+4(x-3)

We multiply parentheses

4x+4x-12

We add all the numbers together, and all the variables

8x-12

Back to the equation:

-(8x-12)



We add all the numbers together, and all the variables

8x-(8x-12)-12=0

We get rid of parentheses

8x-8x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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