(3x+2)/4=(4x+1)/5

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Solution for (3x+2)/4=(4x+1)/5 equation: 



(3x+2)/4=(4x+1)/5

We move all terms to the left:

(3x+2)/4-((4x+1)/5)=0

We calculate fractions


3x/()+(-((4x+1)*4)/()=0



We calculate terms in parentheses: +(-((4x+1)*4)/(), so:

-((4x+1)*4)/(

We multiply all the terms by the denominator


-((4x+1)*4)



We calculate terms in parentheses: -((4x+1)*4), so:

(4x+1)*4

We multiply parentheses

16x+4

Back to the equation:

-(16x+4)



We get rid of parentheses

-16x-4

Back to the equation:

+(-16x-4)



We get rid of parentheses

3x/()-16x-4=0

We multiply all the terms by the denominator


3x-16x*()-4*()=0

We add all the numbers together, and all the variables

3x-16x*()=0

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