3(x-4)+5=12(x+2)

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Solution for 3(x-4)+5=12(x+2) equation: 



3(x-4)+5=12(x+2)

We move all terms to the left:

3(x-4)+5-(12(x+2))=0

We multiply parentheses

3x-(12(x+2))-12+5=0



We calculate terms in parentheses: -(12(x+2)), so:

12(x+2)

We multiply parentheses

12x+24

Back to the equation:

-(12x+24)



We add all the numbers together, and all the variables

3x-(12x+24)-7=0

We get rid of parentheses

3x-12x-24-7=0

We add all the numbers together, and all the variables

-9x-31=0

We move all terms containing x to the left, all other terms to the right

-9x=31

x=31/-9

x=-3+4/9

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