1/4(20-4x)+6x=12x-8x+24

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Solution for 1/4(20-4x)+6x=12x-8x+24 equation:



1/4(20-4x)+6x=12x-8x+24
We move all terms to the left:
1/4(20-4x)+6x-(12x-8x+24)=0
Domain of the equation: 4(20-4x)!=0
x∈R
We add all the numbers together, and all the variables
1/4(-4x+20)+6x-(4x+24)=0
We add all the numbers together, and all the variables
6x+1/4(-4x+20)-(4x+24)=0
We get rid of parentheses
6x+1/4(-4x+20)-4x-24=0
We multiply all the terms by the denominator
6x*4(-4x+20)-4x*4(-4x+20)-24*4(-4x+20)+1=0
Wy multiply elements
24x^2(--16x^2(--96x(-+1=0
We use the square of the difference formula
24x^2(+16x^2(+96x(-1=0

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