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3(x-4)+2=2(4x-5)-5x
We move all terms to the left:
3(x-4)+2-(2(4x-5)-5x)=0
We multiply parentheses
3x-(2(4x-5)-5x)-12+2=0
We calculate terms in parentheses: -(2(4x-5)-5x), so:We add all the numbers together, and all the variables
2(4x-5)-5x
We add all the numbers together, and all the variables
-5x+2(4x-5)
We multiply parentheses
-5x+8x-10
We add all the numbers together, and all the variables
3x-10
Back to the equation:
-(3x-10)
3x-(3x-10)-10=0
We get rid of parentheses
3x-3x+10-10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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