3(x-4)+19=2(6x)

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Solution for 3(x-4)+19=2(6x) equation: 



3(x-4)+19=2(6x)

We move all terms to the left:

3(x-4)+19-(2(6x))=0

determiningTheFunctionDomain
3(x-4)-26x+19=0

We add all the numbers together, and all the variables

-26x+3(x-4)+19=0

We multiply parentheses

-26x+3x-12+19=0

We add all the numbers together, and all the variables

-23x+7=0

We move all terms containing x to the left, all other terms to the right

-23x=-7

x=-7/-23

x=7/23

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