1/7(2x+3)+5=4

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Solution for 1/7(2x+3)+5=4 equation: 



1/7(2x+3)+5=4

We move all terms to the left:

1/7(2x+3)+5-(4)=0



Domain of the equation: 7(2x+3)!=0

x∈R



We add all the numbers together, and all the variables

1/7(2x+3)+1=0

We multiply all the terms by the denominator


1*7(2x+3)+1=0

Wy multiply elements

7x(2+1=0

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