3(x-36)-8(x+28)=16-9(x-33)

Solution for 3(x-36)-8(x+28)=16-9(x-33) equation:

3(x-36)-8(x+28)=16-9(x-33)

We move all terms to the left:

3(x-36)-8(x+28)-(16-9(x-33))=0

We multiply parentheses

3x-8x-(16-9(x-33))-108-224=0


We calculate terms in parentheses: -(16-9(x-33)), so:

16-9(x-33)

determiningTheFunctionDomain
-9(x-33)+16

We multiply parentheses

-9x+297+16

We add all the numbers together, and all the variables

-9x+313

Back to the equation:

-(-9x+313)


We add all the numbers together, and all the variables

-5x-(-9x+313)-332=0

We get rid of parentheses

-5x+9x-313-332=0

We add all the numbers together, and all the variables

4x-645=0

We move all terms containing x to the left, all other terms to the right

4x=645

x=645/4

x=161+1/4