2(3x+4)+10x=72

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Solution for 2(3x+4)+10x=72 equation: 



2(3x+4)+10x=72

We move all terms to the left:

2(3x+4)+10x-(72)=0

We add all the numbers together, and all the variables

10x+2(3x+4)-72=0

We multiply parentheses

10x+6x+8-72=0

We add all the numbers together, and all the variables

16x-64=0

We move all terms containing x to the left, all other terms to the right

16x=64

x=64/16

x=4

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